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fix(tests): terminate find -exec and pass {} — the placeholder step was a no-op #64

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fix(tests): terminate find -exec and pass {} — the placeholder step was a no-op #64

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2 changes: 1 addition & 1 deletion tests/e2e/template_instantiation_test.sh
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Original file line number Diff line number Diff line change
Expand Up @@ -137,7 +137,7 @@ find "$TEST_REPO_PATH" -type f \
sed -i "s|$placeholder|$value|g" "$file"
fi
done
' _ "$file"
' _ {} \;

@codacy-production codacy-production Bot Aug 26, 2026

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🔴 HIGH RISK

The find -exec syntax is now correct, but the subshell logic remains broken. The subshell receives the file path from find as $1, but the script uses "$file". Since the subshell script is single-quoted, it does not have access to the outer shell's $file variable. To fix this, use "$1" directly in the sed command or assign file="$1" at the start of the command string (e.g., sh -c 'file="$1"; sed -i ...').


log_pass "All placeholder tokens replaced"

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